How much is 1 Romanian Leu (Leu) in Romanian Leu Solomon Islands Dollar Leu?

1 RON = 1.8207 SBD

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Romanian Leu

1 Romanian Leu (RON) =
1.8207 SBD (SI$)

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Solomon Islands Dollar

1 Solomon Islands Dollar (SI$) =
0.54924 Romanian Leu (RON)

Last update 20 March 2020 13:19:09
You have just converted 1 RON to SBD - Leu to Solomon Islands Dollar . To convert it, we have used value of 1 RON = 1.8207 Solomon Islands Dollar . You can convert Romanian Leu to any other currency using the above form. Invert exchange - How much is 1 EUR to USD ? Go to USD dollar converter and calculator.